Sunday, March 13, 2011

Stoichiometry involving Lead

Question: 2.00 mol of Pb(NO3)2 is reacted with 3.00 mol of NaCl, determine how grams of PbCl are produced.  Also, find how much Pb(NO3)2 will be leftover.
Stoichiometry:

2.00 mol Pb(NO3)2 x    2 mol NaCl    = 4.00 mol NaCl needed
                              1 mol Pb(NO3)2

3.00 mol NaCl x I mol PbCl   x  242.65 g PbCl  = 363.975 grams of PbCl
                        2 mol NaCl       1 mol PbCl
1.5 mol PbCl x 1 mol Pb(NO3)2 = 1.50 mol Pb(NO3)2 used up. 
                      1 mol PbCl
  2.00 mol available of Pb(NO3)2
- 1.50 mol used up of Pb(NO3)2
  0.50 mol left over of Pb(NO3)2




Question: What is the volume of carbon dioxide gas at STP from the decomposition of 8.54g of lead carbonate?



PbCO3(s) > 2PbO(s) + CO2(g)


Stoichiometry: 
8.54 g PbCO3 x   1 mol PbCO3      x  1 mol CO2     x   22.4 L CO2  = .7159 L CO2 at STP
                        267.21 g PbCO3     1 mol PbCO3        1 mol CO2



No comments:

Post a Comment